1 (edited by nortonka83 2022-04-22 10:25:10)

Topic: How to draw new spirals from existing spirals

Hi

I want to know how I can draw new spirals from existing spirals. I tried the Sum function which repeats the drawing,
but nothing happened.

Is there a way to redraw a function from an old function?
Is it possible to draw a new function from an existing function, and if so, how can I do this by changing the parameters?

Attachments have been shared in the appropriate forum.

Thanks for the help!

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2 (edited by mikk0384 2022-05-29 03:22:18)

Re: How to draw new spirals from existing spirals

I'm not sure this is what you are looking for, but you can swap the constants you need to change regularly out with variables that you define under "Custom functions/constants" (ctrl+F).

It's much easier to keep track of a named variable in that list than finding the right value to change in the formulas every time, and the named variables are shared across functions so you only have to change the value once instead of once for each of the functions.

Re: How to draw new spirals from existing spirals

I'm looking for a formula that, when typed, draws more spirals, as shown in the picture.
It goes without saying that by drawing the figures separately and turning them on one at a time, several spirals can be represented.
But it would be best to draw with a function. The Euler-Maclaurin summary formula is probably
maybe it would solve the problem if we applied it. I don't know how to give him that long formula. But it is also likely that a different summation formula is needed.

It would be a good idea to use two solutions that can solve things that I unfortunately only partially know about.
The sum function is again suitable for iterative drawing of functions, the only problem being that the function is an integer
returns a value, and broken values are needed here, otherwise the spiral will appear piece by piece. Another
option would be the range function.
Using the custom features was only familiar with the keyboard shortcut, which I thank you so much in retrospect, and of course for helping me.