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Sat, 21 Apr 2018 14:37:10 +0000 https://forum.padowan.dk/viewtopic.php?pid=3197#p3197
<![CDATA[Re: Length of curve]]> https://forum.padowan.dk/viewtopic.php?pid=3196#p3196 I don't think that the integral will have a nice solution. Putting the integrand into WolframAlpha, there is not a nice antiderivative of the integrand:

http://www.wolframalpha.com/input/?i=sq … (tx))%5E2)

This might be an integral that will need to be evaluated by numerical methods.

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Sat, 21 Apr 2018 14:21:20 +0000 https://forum.padowan.dk/viewtopic.php?pid=3196#p3196
<![CDATA[Re: Length of curve]]> https://forum.padowan.dk/viewtopic.php?pid=3195#p3195 Dear marcorainaldi

Please where i can see the attached file. i hope from you to send the final solved formula for my function. i know the general formula for the length but i can not solve my this new function f(x)=m*(1+cos(t*x)) from -c to c.

Best regards.

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Sat, 21 Apr 2018 05:49:47 +0000 https://forum.padowan.dk/viewtopic.php?pid=3195#p3195
<![CDATA[Re: Length of curve]]> https://forum.padowan.dk/viewtopic.php?pid=3194#p3194 The general formula for the length of a function f(x) from x=a to x=b is integrate(sqrt(1+[f'(x)]^2),x,-c,c), where f'(x) is the derivative of f(x). See the attached file for an image in proper mathematical notation.

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Sat, 21 Apr 2018 02:21:29 +0000 https://forum.padowan.dk/viewtopic.php?pid=3194#p3194
<![CDATA[Length of curve]]> https://forum.padowan.dk/viewtopic.php?pid=3192#p3192 Dear Ivan,

Could you kindly send to me the formula to calculate the length of f(x)=m*(1+cos(x)) from -c to c

Best regards

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Fri, 20 Apr 2018 11:10:10 +0000 https://forum.padowan.dk/viewtopic.php?pid=3192#p3192